LeahO
New member
If you're just doing the basic recessive dominant (no codominance or mixed models) you can always use the punnett square method where B = black and b = brown:
***Mom B _b (carrier)
Dad B __BB Bb
****B __BB Bb
Red being the possible babies (_ and * for formatting). Each contributes one letter. I'm not a breeder, but I've taken a lot of genetics and this is a model that's easy to understand. You can, of course, end up with no brown carriers at all or all carriers - each egg/sperm has 50% as others have said.
If you have 2 carriers in the future, your chances are 1 in 4 or 25% of being brown (bb):
***Mom B _ b (carrier)
Dad B __BB Bb
(carrier)
****b __ Bb bb
This is a basic page to calculate chances of things, but for many things there are other variables and the ol' square can fall short of reality.
http://www.athro.com/evo/gen/punexam.html
Perhaps you already know, but others might not, so I thought I'd post.
LeahO
***Mom B _b (carrier)
Dad B __BB Bb
****B __BB Bb
Red being the possible babies (_ and * for formatting). Each contributes one letter. I'm not a breeder, but I've taken a lot of genetics and this is a model that's easy to understand. You can, of course, end up with no brown carriers at all or all carriers - each egg/sperm has 50% as others have said.
If you have 2 carriers in the future, your chances are 1 in 4 or 25% of being brown (bb):
***Mom B _ b (carrier)
Dad B __BB Bb
(carrier)
****b __ Bb bb
This is a basic page to calculate chances of things, but for many things there are other variables and the ol' square can fall short of reality.
http://www.athro.com/evo/gen/punexam.html
Perhaps you already know, but others might not, so I thought I'd post.
LeahO
Last edited: